[Collection] 请教主帮忙优化

$处理后数据 = [];
foreach ($原始数据 as $key => $value) {
	$处理后数据[$value['table_name']] = [
		$value['field_name'],
	];
}

好的，我现在去试试，有结果就放上来
==再次编辑，加一下答案
有真相：

$input = '[ { "table_name": "dp", "field_name": "dpcryptfeat", "field_col_num": "6" }, { "table_name": "dp", "field_name": "dppath", "field_col_num": "4" }, { "table_name": "dp", "field_name": "dpauthfeat", "field_col_num": "5" }, { "table_name": "dp", "field_name": "dpnick", "field_col_num": "3" }, { "table_name": "icc", "field_name": "iccbufsizeprot", "field_col_num": "13" }, { "table_name": "icc", "field_name": "iccmech", "field_col_num": "5" }, { "table_name": "icc", "field_name": "iccnick", "field_col_num": "3" }, { "table_name": "icc", "field_name": "iccprocmanager", "field_col_num": "8" }, { "table_name": "icc", "field_name": "iccdesc", "field_col_num": "4" }, { "table_name": "icc", "field_name": "iccprot", "field_col_num": "6" }, { "table_name": "icc", "field_name": "iccformatprot", "field_col_num": "14" } ]';

dd(collect(json_decode($input))->groupBy('table_name')->map(function($item){
    return collect($item)->sortBy('field_col_num')->map(function($data) {
        return $data->field_name;
    })->values();
})->toJson());

哈哈，忍不住试也下。。

collect($groups)->sortBy('field_col_num')->groupBy('table_name')->map(function ($group) {
      return $group->pluck('field_name');
});

这样符合要求么

二位真的太厉害了!